Answer:
x = 17 and y = 37
Step-by-step explanation:
Let the numbers be x and y.
y = 3 + 2x
xy = 629
substituting y in the second equation we get
x(3+2x) = 629
3x + 2[tex]x^{2}[/tex] = 629
2[tex]x^{2}[/tex] + 3x - 629 = 0
Solving a quadratic equation by using its formula:
x = [-3 ±√(9-4(2)(-629)] / 4
x = [-3 ± √5041] / 4
x = [-3 ± 71] / 4
x = 17 and [tex]\frac{-37}{2}[/tex]
Ignore the negative number in x and just use x = 17 in the first equation we get
y = 3 + 2(17) = 37
