Answer:
5 and 61
Step-by-step explanation:
Using Pythagoras' identity in the right triangles
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
(1)
c² = a² + b² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )
c = [tex]\sqrt{25}[/tex] = 5
(2)
c² = a² + b² = 11² + 60² = 121 + 3600 = 3721 ( take the square root of both sides)
c = [tex]\sqrt{3721}[/tex] = 61
