Answer:
the field is not zero anywhere on the x axis (except at infinity)
Explanation:
From the Coulomb's law we have electric field intensity as:
[tex]E=\frac{1}{4\pi.\epsilon_o} \frac{q}{r^2}[/tex]
where:
[tex]\epsilon_o=[/tex] permittivity of free space
[tex]q=[/tex] charge due to which the field is generated.
[tex]r=[/tex] distance from the charge
So, from the above relation:
Electric field due to a charge can only be zero at infinity.
