Answer:
10.86
Step-by-step explanation:
area of parallelogram is equal to║[tex]u[/tex]×[tex]v[/tex]║
solving
now we calculate the cross product
[tex]\left[\begin{array}{ccc}i&j&k\\3&-1&1\\0&3&-2\end{array}\right][/tex]
=[tex]-1i-6j+9k[/tex]
the area of parallelogram is:
║[tex]u[/tex]×[tex]v[/tex]║=[tex]=\sqrt{-1^2-6^2+9^2}[/tex]
=10.86
