Answer:
The particle is 40 m to the right of its initial position.
Explanation:
Given data
- Initial velocity (v₀): 14 ft/s (in direction to the positive x-axis)
- Initial position (s₀): 0 m
- Acceleration (a): -2 ft/s² (in direction to the negative x-axis)
We can determine the position of the particle at a time t = 10 s, using the following kinematic expression.
s = s₀ + v₀.t + 1/2.a.t²
s(10) = 0 m + 14 ft/s × 10 s + 1/2 × (-2 ft/s²) × (10 s)²
s = 40 m
The particle is 40 m to the right of its initial position.
