Answer: The answer to the question is 0.25 ohms
Explanation:
R = u x/A .......1
where u is chosen as the resistivity of
the rod, A is area of the rod and x is
chosen as the length of the rod.
Let R* be the resistance of the
lengths of the rod across the adjoints
Then R* = u1/4.......2
Comparing equation 1 and 2
R* = 1/4
=0.25ohms
