R1a1pencervazMelian R1a1pencervazMelian

11-06-2016
Mathematics

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4x^2-x-3=0 solve by completing the square x= ??

Respuesta :

11-06-2016

Hello,

4x²-x-3=0
==>(2x)²-2*1/2*x+1/4-3-1/4=0
==>(2x-1/2)²-13/4=0
==>(4x-1)²-13=0
==>(4x-1-√13)(4x-1+√13)=0
==> x=(1+√13)/4 or x=(1-√13)/4

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