Answer:
-64
Step-by-step explanation:
You can evaluate as is, substituting the given values for j and k, or you can simplify it first. I like it better without the negative exponents, so I would choose to simplify it at least a bit.
[tex]\left(\dfrac{jk^{-2}}{j^{-1}k^{-3}}\right)^3=(j^{1-(-1)}k^{-2-(-3)})^3=(j^2k)^3[/tex]
Substituting the given values, we get ...
[tex]=((-2)^2(-1))^3=(-4)^3=-64[/tex]
