rmuuse1 rmuuse1

15-09-2019
Physics

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A 4.33 kg cat has 41.7 J of KE How fast is the cat moving?

Respuesta :

joseaaronlara joseaaronlara

15-09-2019

Answer:

The answer to your question is:

Explanation:

Data

mass = 4.33 kg

E = 41.7 J

v = ?

Formula

Ke = (1/2)mv²

Clear v from the equation

v = √2ke/m

Substitution

v = √2(41.7)/4.33

v = 19.26 m/s Result

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