Answer:
Pressure of pressure head will be [tex]863.6pound/ft^2[/tex]
Explanation:
We have given pressure head = 14 feet
Specific weight of water [tex](\rho g)_{water}=62.4pound/ft^3[/tex]
Pressure is given by [tex]P=(\rho g)_{water}h[/tex], here h is pressure head.
So pressure [tex]P=(\rho g)_{water}h=62.4pound/ft^3\times 14ft=863.6pound/ft^2[/tex]
So the pressure of pressure head will be [tex]863.6pound/ft^2[/tex]
