Answer:
-2 and -4
Step-by-step explanation:
The equation [tex]0=-x^{2}-6x-8[/tex]
Can be written as [tex]x^{2} +6x+8=0[/tex]
Lets apply quadratic equation solver:
that is. [tex]x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}[/tex]
where a=1, b=6, c=8
We have [tex]\frac{-6+/-\sqrt{36-32} }{2}[/tex]
The solution is then
x= -2 and x= -4
