skyinspiring4916 skyinspiring4916
  • 13-07-2019
  • Physics
contestada

If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.

Respuesta :

CarliReifsteck CarliReifsteck
  • 18-07-2019

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Charge[tex]q=2\times10^{-4}C[/tex]

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

[tex]V=\dfrac{E}{Q}[/tex]

[tex]V=\dfrac{6.5}{2\times10^{-4}}[/tex]

[tex]V=32500\ volt[/tex]

Hence, The electric potential difference is 32500 volt.

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