15-05-2019
Mathematics

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determine functiion value at x=1 , show your steps [tex](\sqrt{x} -1)/\sqrt[3]{x} -1[/tex]

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15-05-2019

The root of every order of 1 is still 1, in other words, we have

[tex]\sqrt[n]{1}=1[/tex]

So, if we evaluate the function at 1, we have

[tex]\dfrac{\sqrt{1}-1}{\sqrt[3]{1}}-1 = \dfrac{0}{1}-1 = 0-1 = -1[/tex]

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