Answer:
[tex]\boxed{\bold{x=6}}[/tex]
Step By Step Explanation:
Expand [tex]\bold{\left(\sqrt{x-2}\right)^2: \ x-2}[/tex]
Expand [tex]\bold{\left(x-4\right)^2: \ x^2-8x+16}[/tex]
[tex]\bold{x-2=x^2-8x+16}[/tex]
Solve [tex]\bold{x-2=x^2-8x+16: \ x=6,\:x=3}[/tex]
[tex]\bold{x=6,\:x=3}[/tex]
Verify Solutions;
x = 6 - True
x = 3 - False
[tex]\bold{x=6}[/tex]
Regards,
Mordancy
