Answer:
A
Step-by-step explanation:
For factoring, if we can ever right a factor as [tex](a)^2[/tex] and another as [tex](b)^2[/tex] with a MINUS in between them, then the technique of "difference in two squares" is perfect!
From the problem shown, we can actually do this (shown below):
[tex]x^2-25\\=(x)^2-(5)^2[/tex]
The rule is [tex]a^2-b^2=(a+b)(a-b)[/tex]
Thus the problem reduces to:
[tex](x)^2-(5)^2\\=(x+5)(x-5)[/tex]
We have use "difference of two squares" here, hence answer choice A is right.
