Answer:
1. ∗ = 10
2. ∗ = 15ab
Step-by-step explanation:
The identity: (A-B)²=A²-2AB+B² or (A+B)²= A²+2AB+B²
1. In the first problem, A = ∗, which means that ∗² is going to be equal to 100.
∗ = √100= 10
2. In the second problem we already have A and B, and we have both A² (9a²) and B² (6.25b²) and we are missing the "2AB" part in the middle.
∗ = 2AB = 2×3a×2.5b = 15ab
