zuricoco2 zuricoco2
  • 15-12-2018
  • Mathematics
contestada

Find (g - f)(x). f(x) = 1/x g(x) = x2 + 2x -5

A. 1/2-x^2-2x+5
B. 1/x+x^2+2x-5
C. x^2+2x-5-1/x
D. 1/x +x^2-5

Respuesta :

lisboa lisboa
  • 25-12-2018

Answer:

C) [tex]g(x)-f(x)=x^2 + 2x -5-\frac{1}{x}[/tex]

Step-by-step explanation:

[tex]f(x) = \frac{1}{x}  \ g(x) = x^2 + 2x -5[/tex]

To find (g-f)(x) , we need to calculate g(x) - f(x)

WE know f(x) = 1/x  and g(x) = x^2 + 2x -5

Plug in g(x) and f(x) and then subtract

[tex]g(x)-f(x)=x^2 + 2x -5- (\frac{1}{x})[/tex]

All are unlike terms so we cannot combine like terms

[tex]g(x)-f(x)=x^2 + 2x -5-\frac{1}{x}[/tex]

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