Answer:
x = - [tex]\frac{2}{3}[/tex] ± [tex]\frac{\sqrt{19} }{3}[/tex]
Step-by-step explanation:
given a quadratic equation in the form ax² + bx + c = 0
We can solve using the quadratic formula
with a = - 3, b= - 4 and c = 5
x = ( 4 ± [tex]\sqrt{(-4)^2-(4(-3)(5)}[/tex]) / - 6
= ( 4 ± [tex]\sqrt{16+60}[/tex]) / - 6
= ( 4 ± [tex]\sqrt{76}[/tex]) / - 6
= (4 ± 2[tex]\sqrt{19}[/tex]) / - 6
= - [tex]\frac{2}{3}[/tex] ± [tex]\frac{\sqrt{19} }{3}[/tex]
