The slope-intercept form of line:
[tex]y=mx+b[/tex]
We have the slope [tex]m=-\dfrac{1}{4}\to y=-\dfrac{1}{4}x+b[/tex] and the point (-3, -2). Substitute:
[tex]-2=-\dfrac{1}{4}(-3)+b[/tex]
[tex]-2=\dfrac{3}{4}+b[/tex] subtract 3/4 from both sides
[tex]-2\dfrac{3}{4}=b\to b=-\dfrac{11}{4}[/tex]
Answer: [tex]y=-\dfrac{1}{4}x-\dfrac{11}{4}[/tex]
