The given equation is
[tex]\frac{9}{12} = \frac{n}{32}[/tex]
Here we have to solve for n. First we need to get rid of the denominators and for that we do cross multiplication .
[tex]9*32 = 12n[/tex]
Now we need to isolate n. And for that we need to get rid of 12, by dividing both sides by 12
[tex]\frac{9*32}{12}=n[/tex]
[tex]\frac{288}{12} =n[/tex]
[tex]n=24[/tex]
And that's the required value of n .
