Let Yancy's age be = x years
Let her sister's age be = y years
Given is , Yancy is 2 years older than 3 times her younger sister's age, so equation is formed like
[tex]x=2+3y[/tex] .... (1)
Also given, as her younger sister is 6 years old.
So, y=6
Putting y= 6 in equation (1)
[tex]x=2+3(6)[/tex]
[tex]x=2+18[/tex]
[tex]x=20[/tex]
Hence, Yancy is 20 years old.
