Alisam7449 Alisam7449
  • 13-06-2018
  • Mathematics
contestada

Write an equation in intercept form of the parabola that passes through the point (3,40) and has x-intercepts −5 and 4.

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altavistard
altavistard altavistard
  • 19-06-2018
The equation of this parabola will have the form f(x) = a(x+5)(x-4), which works out to f(x) = a(x^2 + x - 20).  Since the parabola passes thru (3,40),

40 = a(3^2 + 3 - 20), or 40 = a(-8), so a = -5.

Thus, the equation of this parabola is     y = -5(x^2 + x - 20).
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