jasssminne jasssminne

12-06-2018
Mathematics

contestada

Wat 4x + 8y=40 when y=0.8?

Respuesta :

12-06-2018

Hey there! :)

First, let's substitute y with 0.8, and multiply by 8

0.8 × 8 = 6.4

Here is the new equation:

4x + 6.4 = 40

Now, subtract 6.4 from 40

40 - 6.4 = 33.6

That means 4x = 33.6

Divide both by 4

4x ÷ 4 = x
33.6 ÷ 4 = 8.4

x = 8.4

Hope this helps :)

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