laurinelionise6 laurinelionise6

12-12-2022
Mathematics

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14. In the figure (not drawn to scale), MO bisects LMN, mZNMO = (6x + 19), and m 14). Solve for x and find ZLMN.
L
M
A. x= 11, m LMN = 198°
B. x= 11, m ZLMN = 170°
N
C. x=8, m ZLMN = 25°
D. x=8, m ZLMN = 54°

14 In the figure not drawn to scale MO bisects LMN mZNMO 6x 19 and m 14 Solve for x and find ZLMN L M A x 11 m LMN 198 B x 11 m ZLMN 170 N C x8 m ZLMN 25 D x8 m class=

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